By A. C. Burdette (Auth.)

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**Extra resources for Analytic Geometry**

**Sample text**

There is no symmetry with respect to the coordinate axes. (c) Extent: We solve for x, using the quadratic formula, and obtain x = 1 ± y/i - 4y2 o ' If y2 > J, that is, if \y\ > ^, x is imaginary. Hence these values of y are excluded, and we see that the curve lies completely within a strip of width \ unit on either side of the x axis. The value y — 0 will be dealt with in (d) below. Now we solve for y and obtain x From this we note that any real value of x gives a real value for y. Hence we conclude that there are no excluded values of x.

9. Find the equation of the line that has the y intercept 4 and is parallel to the line 2x — 3y = 7. 10. Find the equation of the line that has the x intercept — 3 and is perpen dicular to the line 3x + 5y — 4 = 0. 11. The perpendicular from the origin to a line meets it at the point ( — 2, 9). Find the equation of the line. 12. By using equations of lines, prove the three points (3,0), ( — 2, —2), (8, 2) are collinear. 13. Find the equation of the perpendicular bisector of the segment of the line 3x — 2y = 12 which is intercepted by the coordinate axes.

This does not require any definition of directions because a positive direction has already been assigned on the normal to a line. For example, we see in Figure 2-11 that dl is negative because it is measured opposite the positive direction on the normal. For similar reasons d2 is positive. In general, 38 2. THE STRAIGHT LINE , v, "V. Pi \ y \ l \ 0 Pi X P(x» yù Figure 2-11 Figure 2-12 if P and the origin are on opposite sides of the line, the directed distance will be positive ; if they are on the same side, it will be negative.